A particle of mass M is moving in a horizontal circle of radius R with uniform speed V . When

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5.Work, Energy, Power and Collision

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A particle of mass $ M$ is moving in a horizontal circle of radius $R$ with uniform speed $V$. When it moves from one point to a diametrically opposite point, its

A

Kinetic energy changes by $M{V^2}/4$

B

Momentum does not change

C

Momentum changes by $ 2MV$

D

Kinetic energy changes by $M{V^2}$

(AIPMT-1992)

Solution

(c) On the diametrically opposite points, the velocities have same magnitude but

opposite directions. Therefore change in momentum is

$\mathrm{Mv}-(-\mathrm{M} \mathrm{v})=2 \mathrm{Mv}$

Standard 11

Physics

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